.0025 =2/5^a × 10^b
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Given : 0.0025 = [2/5]^a ×10^b
To Find : Value of a and b
Solution:
0.0025 = [2/5]ᵃ ×10ᵇ
=> 0.0025 =(2ᵃ/5ᵃ) × 10ᵇ
=> 0.0025 =(2ᵃ/5ᵃ) ×(2 × 5 )ᵇ
=> 0.0025 =(2ᵃ/5ᵃ) × 2ᵇ × 5ᵇ
=> 0.0025 = 2ᵃ⁺ᵇ ₓ 5ᵇ⁻ᵃ
=> 25/10000 = 2ᵃ⁺ᵇ ₓ 5ᵇ⁻ᵃ
=> 1/400 = 2ᵃ⁺ᵇ ₓ 5ᵇ⁻ᵃ
=> 1/(2* 2 * 2 * 2 * 5 * 5) = 2ᵃ⁺ᵇ ₓ 5ᵇ⁻ᵃ
=> 1/(2⁴ * 5²) = 2ᵃ⁺ᵇ ₓ 5ᵇ⁻ᵃ
=> 2⁻⁴ * 5⁻² = 2ᵃ⁺ᵇ ₓ 5ᵇ⁻ᵃ
2 and 5 are co prime
Hence equating powers of corresponding bases
=> a + b = - 4
b - a = - 2
=> 2b = - 6
=> b = - 3
=> a = - 1
Learn More:
a^3+b^4=c^5 ,
brainly.in/question/39118996
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