Question

01. A trihybrid mullato man marries with a white
woman, how many different types of phenotypes
will be obtained ?
(1) 2 (2) 3 (3) 4 (4)5
​

Answer 1

Answer:

two types of pheontype will obtain.

either mullato or white

Answer 2

Answer:

Four phenotypes will be formed.

Explanation:

• Mulato man genotype- AaBbCc
• Albino (white) woman genotype- aabbcc
• Mulato man can produce 8 different gametes whereas the albino woman can produce 1 type of gamete.
• Phenotypes obtained will be- 1 mulato, 3 fair, 3 light, and 1 albino.
• Mendel tested three sets of contrasting traits in some of his hybrids. Trihybrid crosses are one type of such cross. Three separate monohybrid crosses are combined to form a trihybrid cross. Examples include seed shape (round vs. wrinkled), seed color, and plant height (tall vs. small) (yellow vs. green).
• Eight gametes are produced by the trihybrid cross's F1 generation plants, which are heterozygous for all three characteristics. These gametes have an equal probability of producing 64 different genotype combinations in the F2 generation after self-fertilization.

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