Question

01
AABC is right angled at A with AB = 6 cm, BC = 10 cm. A circle with centre O has been
inscribed inside the triangle. The radius of the incircle is,
4cm
3 cm
2 cm
1 cm​

Answer 1

Answer:

Using Pythagoras theorem in △ABC

(AB)

2

+(BC)

2

=(AC)

2

(8)

2

+(6)

2

=(AC)

2

⇒(AC)

2

=64+36=100

⇒AC=10cm

Now inradius of triangle =r=

s

Δ

where Δ is the area of triangle and s is semi perimeter

Δ=

2

1

×8×6=24

s=

2

8+6+10

=

2

24

=12

⇒x=r=

s

Δ

=

12

24

=2cm

Answer 2

Answer:

4 cm

..

.

.....

....................