Question

01
Evaluate (2x+1)(x+2)(2x-1)​

Answer 1

Step-by-step explanation:

(2x)2 + (1x1x)2 – 2 (2x)(1x1x) [(a – b)2 = a2 + b2 – 2ab] = 4x2+1x2−44x2+1x2−4 (ii) (2x + y) (2x – y) (2x + y) (2x – y) [(a – b)(a + b) = a2 – b2] = (2x )2 – (y)2 = 4x2 – y2 (iii) (a2b – b2a)2 (a2b – b2a)2 [(a – b)2 = a2 + b2 – 2ab] = (a2b)2 + (b2a)2 – 2 (a2b)( b2a) = a4b2 + b4a2 – 2a3b3 (iv) (a – 0.1) (a + 0.1) (a – 0.1) (a + 0.1) [(a – b)(a + b) = a2 – b2 ] = (a)2 – (0.1)2 = (a)2 – 0.01 (v) (1.5 x2 – 0.3y2) (1.5 x2 + 0.3y2) (1.5 x2 – 0.3y2) (1.5x2 + 0.3y2) [(a – b)(a + b) = a2 – b2 ] = (1.5 x2)2 – (0.3y2)2 = 2.25 x4 – 0.09y4Read more on Sarthaks.com - https://www.sarthaks.com/603611/evaluate-2x-1-x-2.

Answer 2

Answer:

answer is given in the picture

thanks