Math, asked by imranansari8014, 11 months ago


01. How much fall in Fahrenheit temperature, if a piece of red hot MS rod was lowered from
900°C to 200°C by dipping in water?
a) 1298F
c) 1286F
b) 1292F
d) 1284F

02. What is the distance between the load and point of force, if the lever has to support a
100 kg load at 50cm from fulcrum with 17 kg force at the end of lever to keep in
equilibrium?


a)244.1 cm
b)254.1 cm
c)264.1 cm
d)274.1 cm​

Answers

Answered by amitnrw
1

1260°F  drop in temperature if lowered from 900°C to 200°C by dipping in water

Step-by-step explanation:

Fahrenheit temperature  = 1.8 Celsius Temperature  + 32

1.8 * 900 + 32 = 1620 + 32 = 1652

900°C  = 1652 °F

1.8 * 200 + 32 =360 + 32 = 392

200°C  = 392 °F

Drop in Fahrenheit

1652 °F - 392 °F  =   1260°F

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Answered by tudumotu4
0

Answer:

Step-by-step explanation:

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