Math, asked by pavithrambr005, 8 months ago

01. The average age of a man and his son is 28 years. The ratio of their ages is 3:1 respectively. What is the man's age?​

Answers

Answered by sabina55
0

Answer:

Four years ago,

Let, Father's age = 10x years

Son's age = 3x years

Therefore, 10x + 3x + 8 = 60

=>13x = 60 - 8 = 52 => x = 4

Therefore, Required difference = 7x = 7×4 = 28 years

Answered by potaganiharshapa9p16
3

Answer:

As the ratio of the father and his sons age is 3:1

=> let the father age be x and sons age be y

Therefore from the given condition x=3y

there fore

x+y=28*2

4y=28*2

therefore y= 14

Step-by-step explanation:

and man's age is 14*3= 42

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