Question

01. The brakes applied to a car produce an acceleration of 6 m s-2 in the
opposite direction to the motion. If the car takes 2 sto stop after the
application of brakes, calculate the distance it travels during this time,
(s=12m)​

Answer 1

Explanation:

Acceleration a = -6 m/s^2

Time t = 2 s

Final velocity v = 0 m/s

Let initial velocity be u

Let distance be s

v = u + at

So, 0 = u + (-6)(2)

So, u = 12 m/s

Now, s = ut + (1/2) at^2

So, s = 12(2) + (1/2)(-6)(2^2)

So, s = 24 - 12

So, s = 12 m

Thus, distance travelled is 12 m