Question

01.
The number of electron in 3.1 mg NO, is (NA = 6 x 1023)
(A)32
(B) 1.6 x 10-3
(C) 9.6 x 1020
(D) 9.6 x 1023​

Answer 1

option c is the right answer

9.6 x 1020

Answer 2

Answer:

i think it is usefull for you and please mark as brailiest answer