Question

01
VICIN TITOVICW
02
A block of mass 13 kg is kept on a spring
having a spring constant of 520 N/m.
The spring is compressed for 50 cm and
then released. Determine the height up to
which the block rises.
(Note: Use g = 10 m/sec2)
A. 0 62 cm
B.
50 cm
C.
55 cm
D. O 64 cm
Mark for review​

Answer 1

The given question is A block of mass 13 kg is kept on a spring

having a spring constant of 520 N/m.

The spring is compressed for 50 cm and

then released. Determine the height up to

which the block rises.

(Note: Use g = 10 m/sec2)

The given data in the above question is

As block falls on a spring, the change in the gravitational potential energy which become kinetic energy, then energy starts to transform to potential energy due to the displacement of the spring as

$mgh = \frac{1}{2} k {x}^{2}$

where m is the mass of the block = 13 kg

h is the height which the block rises = ?

g is acceleration due to gravity = 10 meter per second square

k is the spring constant = 520 N/M

x is the maximum compression in the spring = 50 cm

substituting these values in the above formula we get

$(13)(10)(h) = \frac{1}{2} \times 520 \times 50 \times 50$

$130h = 650000 \\ h = \frac{650000}{ 130} \\ = 5000$

The height which the block rises is 5000cm

which is 50 m.

The option B is correct

# spj2

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