Question

010. If D = ABC + BCA + CAB where A, B and C are decimal digits, then D is divisible by
a. 37 and 29
C. 29 but not 37
b. 37 but not 29
d. neither 29 nor 37​

Answer 1

Answer:

D is  divisible by  37 but not 29

Step-by-step explanation:

Given:

D = ABC + BCA + CAB

This can be written as

D = (100A+10B+C)+(100B+10C+A)+(100C+10A+B)

Grouping, we get

D = 100(A+B+C)+10(A+B+C)+(A+B+C)

Taking A+B+C as common

D = (100+10+1)(A+B+C)

D = (111)(A+B+C)

D = (37*3)(A+B+C) which is divisible by 37 but not 29