Question

011) In a triangle two angles are equal while the third angle is equal to the sum of the first two.
Find the measure of each angle of the triangle.​

Answer 1

let the 1st and 2nd be x

1st angle = x

2nd angle = x

3rd angle = x+x

sum of all angles = 180°

x+x+2x = 180°

4x = 180°

x =180°

x = 180° /4

x = 45°

1st angle = 45°

2nd angle = 45°

3rd angle =2 ×45° =90°

HERE IS YOUR ANSWER....