Question

014. Find so that:
(2/9)⁷ × (2/9)² = (2/9)^2x-1

Guys pls help
and no scam pls​

Answer 1

Solution:-

${ (\frac{2}{9}) }^{7} \times { (\frac{2}{9}) }^{2} = { (\frac{2}{9}) }^{2x - 1} \\ \\ { (\frac{2}{9}) }^{9} = { (\frac{2}{9}) }^{2x - 1} \\ \\ compare \: both \: side \\ 9 = 2x - 1 \\ 10 = 2x \\ 5 = x \\ x = 5$

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