Math, asked by tunesofdarkshadows00, 4 months ago

015. The equation of straight line
passing through the point (1, 2)
and parallel to the line y = 3x + 1 is
(A) y + 2 = x + 1
(B) x + 2 = 3 (x + 1
(c) Y - 2 = 3 (x - 1)
(D) Y - 2 = x 1
y​

Answers

Answered by Madankumar808103
0

Answer:

015. The equation of straight line

passing through the point (1, 2)

and parallel to the line y = 3x + 1 is

(A) y + 2 = x + 1

(B) x + 2 = 3 (x + 1

(c) Y - 2 = 3 (x - 1)

(D) Y - 2 = x 1

y

Answered by Anonymous
2

Step-by-step explanation:

QUESTION IS 015. The equation of straight line

passing through the point (1, 2)

and parallel to the line y = 3x + 1 is

(A) y + 2 = x + 1

(B) x + 2 = 3 (x + 1

(c) Y - 2 = 3 (x - 1)

(D) Y - 2 = x 1

y

ANSWER IS (B) x + 2 = 3 (x + 1

PLEASE MARK AS BRAINLIST AND FOLLOW ME FOR MORE QUALITY TYPE OF ANSWER THANK YOU. HAVE A GREAT DAY.

Similar questions