Question

01521 15
. Right angle triangle at P ( ∆ PQR ) where PR= 4 cm PQ=3 cm
find RQ=?​

Answer 1

Answer:

Using pythagoras theorem

pq = 3 cm

pr = 4 cm

to find : qr

${pq}^{2} + {pr}^{2} = {qr}^{2} \\ {3}^{2} + {4}^{2} = {qr}^{2} \\ 9 + 16 = {qr}^{2} \\ {qr}^{2} = 25 \\ {qr}^{2} = {5}^{2} \\ qr = 5$

Answer 2

Answer:

this is correct.....................