Question

018. A substance on analysis was found to contain C= 11.39%, Na= 43.4% and O=45.3%. Determine the empirical
formula The molecular mass of this compound is 106 unit. Determine ts molecu ar formula.​

Answer 1

✌✌hey dude here is ur ans✌✌

ANSWER

Dividing their percentages by their atomic weights.

Sodium=2343.4=1.88

Carbon=1211.3=0.941

Oxygen=1645.3=2.83

Dividing all these numbers with simple numbers

Sodium=0.941.88=2

Carbon=0.940.94=1

Oxygen=0.942.83=3

Their ratio 2:1:3 

Empirical formula = Na2Co3..

Hope it helps you .. if it is then thank me... and please like my another answer also...thanku✌✌☺️☺️