Question

02:03
Q 16 In an examination Paul scored 15 marks more than Peter and his marks were 75% of the sum of these canite z dzelt
examination.
Ops: A.
0 20.2
B. 12.5
C. 13.5
D. 22.5​

Answer 1

Answer:

Paul = 22.86 and Peter = 12.86.

Step-by-step explanation:

In an examination paul scored 10 marks more than peter.

Let the marks of paul be x.

Marks of perter = x-10

Sum of their marks = x + (x-10) = 2x-10

Paul marks were 64% of their marks.

x=(2x-10)\times \frac{64}{100}

x=(2x-10)\times 0.64

x=1.28x-6.4

Subtract 1.28x from both sides.

x-1.28x=-6.4

-0.28x=-6.4

Divide both sides by -0.28.

x=\frac{-6.4}{-0.28}

x\approx 22.86

The value of x is 22.86, therefore

Marks of Paul = x = 22.86

Marks of perter = 22.86-10 = 12.86