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Find the largest four-digit number which
When divided by 4, 7 and 13 leaves a
remainder 3 in each case.
[2 mark​

Answer 1

$question$

Find the largest four-digit number which When divided by 4, 7 and 13 leaves a remainder 3 in each case

$answer$

Prime factors of 4,7 and 13

4=2×2

7 and 13 are prime numbers

LCM (4,7,13)=36

we know that, the largest 4 digit number is 9999.

Step 1 : divide 9999 by 364, we get

364

9999

=171

Step 2: subtract 171 from 9999

9999−171=9828

Since a remainder of 3 is to be left

9282+3=9831