Question

02-
1. An object changes its velocity from 10 m/s to 20 m/s having mass 50 kg
find the work done in terms of change in kinetic energy.​

Answer 1

Answer:

2500kgm/s

Explanation:

kinetic energy is 1/2(mv^2)

mass is 50kg

v is 20-10 =10

so 1/2*(50*10*10)

=2500

Answer 2

Explanation:

according to work energy theorem

work done = change in kinetic energy

here in question

intial kinetic energy = 1/2 × 50 × (10×10) = 2,500 J

final kinetic energy = 1/2 × 50 × (20×20) = 10,000J

so work done by external agent =

(10,000-2,500)

= 7,500Joule