Math, asked by mukeshlucky0067, 1 month ago

02. 1 Three machines P , P., and P, in a certain factory produce 50%, 50% and 25%, 2 3. respectively, of the total daily output of electric tubes. It is known that 5% of the tubes produced by each of the machines P, and P, are defective and that 4% of those produced on P3 are defective. If one tube is picked up at random from a day's production, calculate the probability that the defective tube was produced on machine P1 Ops: А. 8/7 B. 6/7 С. 5/7 D 9/7​

Answers

Answered by rewatiramantiwari307
0

Answer:

Let A1 : Event that the bulb is produced by machine E1 A2 : Event that the bulb is produced by machine E2 A3 : Event that the bulb is produced by machine E3 A : Event that the picked up bulb is defective Here, P(A1) = 50% = 50/100 = 1/2, .'. The probability that the picked bulb is defective, Read more on Sarthaks.com - https://www.sarthaks.com/203233/three-machines-and-certain-factory-producing-electric-bulbs-produce-50-25-respectively

Step-by-step explanation:

Hope it helps you friend

Similar questions