Question

02^2x+3=65(2^x-1)+57

Plz answer this question and I'll mark ur ans as brainiest ans​

Answer 1

Answer:

BRAINLEST!!

Equation is in the Form = 22x+3 = 65 (2x - 2 ) + 122

=> 22x . 23 = 65 ( 2x - 2 ) + 122

=> 8(2x)2 = 65 ( 2x - 2) + 122

Put 2x = y , We get

=> 8y2 = 65(y-2) + 122

=> 8y2 = 65y - 130 + 122

=> 8y2 - 65y + 8 = 0

=> 8y2 - 64y - y + 8 = 0

=> 8y ( y - 8) - 1(y-8) = 0

=> (8y-1) ( y - 8) = 0

Either 8y -1 = 0 or y - 8 = 0

So, y = 1/8 or 8

=> 2x = 1/8 or 2x = 8

=> 2x = (2)-3 or 2x = (2)3

On comparing, We get

x = -3, 3