Question

02. A bullet is fired horizontally with a velocity of 200 ms
If acceleration due to gravity is 10 ms2? in first second it
will fall through a height of
(a) 5'm
(b) 10 m
20 m
(d) 200 m.
please explain the answer​

Answer 1

in first second it will fqal through a night of 20m

Answer 2

Aɴꜱᴡᴇʀ

$\huge{\sf{\red{H_y=5m}}}$

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Gɪᴠᴇɴ

• Intial horizontal velocity of bullet = 200mps

• Acceleration due to gravity = 10m/s^2

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ᴛᴏ ꜰɪɴᴅ

• Verticle distance covered by bullet in first second.

_________________

Sᴛᴇᴘꜱ

Solution :

✴ Given :-

✴ To Find :-

▪

Verticle distance covered by bullet in first second. use:-

Here we use:-

• This question is completely based on concept of projectile motion (Height to ground).

• In this case, verticle velocity of bullet is zero.

• Gravitational acceleration acts in downward direction.

• We can solve this question with the help of the third equation of kinematics

So,

$\begin{lgathered}\dashrightarrow\bf\:H_y=u_yt+\dfrac{1}{2}gt^2\\ \\ \leadsto\sf\:H_y=(0\times 1)+(\dfrac{1}{2}\times 10\times 1^2)\\ \\ \leadsto{\sf{\pink{H_y=5m}}}\end{lgathered}$

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$\huge{\mathfrak{\purple{hope\; it \;helps}}}$