Question

02
A cas starts moving from rest and attaine a velocity of 10 m/s
in 5 minutes. If the accelera
tion is constant, The calculate
(1)Acceleration
(2)Distance travelled by the car​

Answer 1

Answer:

rest means u=0

V=10

t=5 min.

a=v+u/t=2m/S*S

s=ut+1/2at*t

s=50+25

75 m

Answer 2

Answer:

intial velocity u=0m/s

finial velocity v=10m/s

time t=5min

v=u+at (first equation of motion)

10=0+a*5

10=a*5

a=10/5

a=2m/s^2

s=ut+1/2a*t^2 (2nd eqn of motion)

s=0*5+(.5*2*((5)^2)

s=.5*2*25

s=25m