Physics, asked by rohankale988, 19 days ago

02. A small ball is projected horizontally between two large blocks. The ball is given a velocity V m/s and the large blocks move uniformly with a veloc- ity of 2V m/s. The ball collides elastically with the blocks. If the velocity of the blocks do not change due to the collision, then find out the velocity of the ball after the 2nd collision V (2K, -v )= (v-2v) va av Assume friction to be absent 1) 5 V 2) 7 V 9V 3) 4) None of these 1​

Answers

Answered by kanchankumari0201198
0

Explanation:

Correct option is B)

Forfirstcollision

velocityofseperation=−e(velocityofapproach)

(−V

1

−2V)=−(V−2V)

Forsecondcollision

velocityofseperation=−e(velocityofapproach)

(V

2

−2V)=−(V

1

−2V)

⇒V

2

=7V

Answered by XxBeastxX2121
0

7 v

. A small ball is projected horizontally between two large blocks. The ball is given a velocity V m/s and the large blocks move uniformly with a veloc- ity of 2V m/s. The ball collides elastically with the blocks. If the velocity of the blocks do not change due to the collision, then find out the velocity of the ball after the 2nd collision V (2K, -v )= (v-2v) va av Assume friction to be absent 1) 5 V 2) 7 V 9V 3) 4) None of these 1

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