02) A tangent PQ at a point P of a circle of radius 5 cm meets
the centre O at a point Q so that OQ = 12 cm. Length PQ is :
A)12 cm B) 13 cm C) 8.5 cm D) V119 cm
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Answer:
∆OPQ is a right angled triangle at /_P
by using pythagoras theorem.,
OP^2+PQ^2=OQ^2
OP^2=12×12-5×5
OP^2=144-25
OP=√119 cm
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