Question

02.
check whether – 2 and 2 are the zero es of the polynomial
22² +3.​

Answer 1

Answer:

Here, we will use remainder theorem.

p(x) = x⁴ - 16

Now, p(2) = (2)⁴ - 16

\implies⟹ p(2) = 16 - 16

\implies⟹ p(2) = 0

\therefore∴ 2 is a zero of the polynomial.

Now, p(-2) = (-2)⁴ - 16

\implies⟹ p(-2) = 16 - 16

\implies⟹ p(-2) = 0

\therefore∴ (-2) is also a zero of the polynomial.

Hence proved.