Question

02. Find the number of K ions in 3.41 mol of K2HPO4?​

Answer 1

Explanation:

There are two K^+ ions in every formula unit of K2HPO4

3.41 mol K2HPO4 times 2 mol K^+ / mole K2HPO4 = 6.82 mol K^+

In one mole of anything, there are 6.022 x 10^23 representative particles.

6.82 mol K^+ times 6.022 x 10^23 K^+ ion / mole K^+ ions = 4.107004 x 10^24 K^+ ions

to three sig figs, the answer is 4.11 x 10^24 K^+ ions

Answer 2

The correct answer is 3.6132 × 10²² ions of Potassium.

GIVEN

Moles of K₂HPO₄ = 3.41 mol

TO FIND

Number of K₂HPO₄ ions

SOLUTION

We can simply solve the above problem as follows;

Dissociation of K₂HPO₄ -

K₂HPO₄ -----------> 2K⁺ + (HPO₄)⁻²

This means that 1 molecule of k₂HPO₄ gives two ions of potassium.

We know that,

1 mole of K₂HPO₄ = 6.022×10²³ molecules of K₂HPO₄

Therefore,

1 mole of K₂HPO₄ will give, 2 × 6.022×10²³ ions of potassium.

So, 3.14 moles of K₂HPO₄ will give, 3.14 × 2 × 6.022×10²³ = 3.6132 × 10²² ions of Potassium.

Hence, The correct answer is 3.6132 × 10²² ions of Potassium.

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