Question

02
Given below is a circle with centre 0 and DE is an arc of a circle with centre B. If BC = 1 cm and BE =
$\sqrt{5} cm$
cm, what is the length of OB

Answer 1

Answer:

Cuemath Leap

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02

Given below is a circle with centre 0 and DE is an arc of a circle with centre B. If BC = 1 cm and BE =

$\sqrt{5} cm$

cm, what is the length of OB?

D

1cm

ТЕ

С

O

B

А

15 cm

Step-by-step explanation:

very long...

Answer 2

Answer is OB = 2 cm

BE=BD=

OB=OC-1

OD=OC

Find the length of OD using pythagoras.

After writing the equation replace OD and OB with above mentioned values. And write root 5 in place of BD.

Entire equation will be in terms of OC. Solve to find that OC is 3cm.

The OB automatically becomes 2 cm.