Question

02. If the unit's digit in the product (47x x 729 x 345 x 343) is 5, what is the maximum
number of values that x may take?
(a) 9
(b)3
(c) 7
(d) 5
​

Answer 1

Hey mate here we go

As per Ur question the maximum value of X

multiple of unit digit is 5

i.e.,

$x \times 9 \times 5 \times 3 = \: \: \: 5$

as we multiplying those numbers we will get

9*5*3= 135

then if we multiple by 9 we will get 1215

So 9 is maximum num

I hope this will helps you

mark my ans as brainliest

Answer 2

Answer:

(d) 5

Step-by-step explanation:

$47x \times 729 \times 345 \times 343 = 47x \times 862,66,215$  

It is given that the units digit of $47n \times 862,66,215$ or $n \times 5$ is $5$.

Therefore, the values of $n$ can be any odd digit, i.e., $1, 3, 5, 7$ and $9$.

Hence, the maximum  number of values that $x$ may take is $5$.