02.in a hydraulic machine, the two pistons are of area of cross section in the ratio 1:20. What force is needed on the wider piston to overcome a force of 10 N on the narrow piston?
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Answer:
ANSWER
F
1
=100NA
1
=10m
2
F
2
=xNA
2
=1m
2
Since pressure = constant
hence,
A
1
F
1
=
A
2
F
2
⇒
10
100
=
1
x
x=10N
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