Question

02.in a hydraulic machine, the two pistons are of area of cross section in the ratio 1:20. What force is needed on the wider piston to overcome a force of 10 N on the narrow piston?​

Answer 1

Answer:

ANSWER

F

1

=100NA

1

=10m

2

F

2

=xNA

2

=1m

2

Since pressure = constant

hence,

A

1

F

1

=

A

2

F

2

⇒

10

100

=

1

x

x=10N

Answer By

Explanation:

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