Math, asked by vidhyabehare8, 7 months ago

02 Show that the following sets of points are the vertices of
right isosceles triangle
(i) (0,0),(5,5) and (5,-5)
(ii) (3,-1),(5,-1) and (,-8)
(iii) (0,-4), (3/2-1) and (3,0)

Answers

Answered by gaurav042005
1

Answer:

Step-by-step explanation:

We know that the distance between the two points (x  

1

​  

,y  

1

​  

) and (x  

2

​  

,y  

2

​  

) is  

d=  

(x  

2

​  

−x  

1

​  

)  

2

+(y  

2

​  

−y  

1

​  

)  

2

 

​  

 

Let the given vertices be A=(8,−4), B=(9,5) and C=(0,4)

We first find the distance between A=(8,−4) and B=(9,5) as follows:

AB=  

(x  

2

​  

−x  

1

​  

)  

2

+(y  

2

​  

−y  

1

​  

)  

2

 

​  

=  

(10−2)  

2

+(1−1)  

2

 

​  

=  

8  

2

+0  

2

 

​  

=  

64

​  

=8

Similarly, the distance between B=(9,5) and C=(0,4) is:

BC=  

(x  

2

​  

−x  

1

​  

)  

2

+(y  

2

​  

−y  

1

​  

)  

2

 

​  

=  

(6−10)  

2

+(9−1)  

2

 

​  

=  

(−4)  

2

+8  

2

 

​  

=  

16+64

​  

=  

80

​  

=  

4  

2

×5

​  

=4  

5

​  

 

Now, the distance between C=(0,4) and A=(8,−4) is:

CA=  

(x  

2

​  

−x  

1

​  

)  

2

+(y  

2

​  

−y  

1

​  

)  

2

 

​  

=  

(6−2)  

2

+(9−1)  

2

 

​  

=  

4  

2

+8  

2

 

​  

=  

16+64

​  

=  

80

​  

=  

4  

2

×5

​  

=4  

5

​  

 

We also know that If any two sides have equal side lengths, then the triangle is isosceles.

Here, since the lengths of the two sides are equal that is BC=CA=4  

5

​  

 

Hence, the given vertices are the vertices of an isosceles triangle.

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Answered by vaishnavi45883
1

Answer:

(ii)

Step-by-step explanation:

(3,-1),(5,-1),(0,-8)

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