Question

02. The length of the diagonal of the cuboid of dimension 8m x 4m x 6m is​

Answer 1

Step-by-step explanation:

Length of diagonal of cubiod= square root of (8sqaure + 4sqaure + 6sqaure)

diagonal= square root of (64+16+36)

diagonal= square root of (116)

diagonal= 10.7703m

Answer 2

Answer :-

• Diagonal of cuboid = 10.77 cm

Given :-

• Length of cuboid = 8 cm
• Width of cuboid = 4 cm
• Height of cuboid = 6 cm

To Find :-

• Diagonal of cuboid = ?

Explanation :-

As we know, we have formulae to find the diagonal of cuboid .

$\blue { \boxed { \bf \bigstar \; Diagonal \; of \; Cuboid = \sqrt{(L)^2+(B)^2+(H)^2} \; \; \bigstar }}$

$\rm : \; \longmapsto \sqrt{(8)^2+(4)^2+(6)^2} \; \; \; cm$

$\rm : \; \longmapsto \sqrt{(64)+(16)+(36)} \; \; \; cm$

$\rm : \; \longmapsto \sqrt{(80)+(36)} \; \; \; cm$

$\rm : \; \longmapsto \sqrt{(116)} \; \; \; cm$

$\rm : \; \longmapsto \sqrt{116} \; \; \; cm$

$\green { \underline { \boxed { \bf : \; \longmapsto 10.77 \; \; \; cm}}} \qquad \bf [Approx.]$

Hence, the diagonal of the of the cuboid is 10.77 cm.

$\huge \text{\underline{\underline{More To Know}}}$

$\rm \star \; Diagonal \; of \; Cuboid = \sqrt{(L)^2+(B)^2+(H)^2}$

$\rm \star \; Diagonal \; of \; Cube = \sqrt{3} \; (Side)$

$\rm \star \; TSA \; of \; Cuboid = 2 \; (LB+BH+HL)$

$\rm \star \; TSA \; of \; Cube = 6(Side)^2$

$\rm \star \; LSA \; of \; Cuboid = 2H\; (L+B)$

$\rm \star \; LSA \; of \; Cube = 4(Side)^2$