Question

02. The speed of homogeneous solid sphere after
rolling down on inclined plane of vt. ht. h
from rest without sliding is [ AIPMT -92]
1)√10/7gh
2)√gh
3)√6/3gh
4)√4/3gh
​

Answer 1

√6/3gh c answer is right

Answer 2

Answer:√10/7gh

Explanation:

Initially,v=0 and w=0. Height=h. P.E=mgh. Finally,v,w,h=0. K.E=1/2mv^2+1/2IW^2. =1/2mv^2+1/2.2/5mR^2.v^2/R. =mv^2/2+mv^2/5. K.E=7mv^2/10. Work Energy Theorem,. mgh=7/10mv^2. v=√10/7gh