Question

020
construct a A P Q R in which QR-6
cm, P Q = 404 cm
and PR = 5 3cme
Draw the bisector
of <P.​

Answer 1

Answer:

Steps of constructions:

(1) Draw seg QR of length 4.2 cm.

(2) Draw ray QT such that ∠RQT=40

∘

(3) Mark point S on ray QT such that QS=8.5cm

(4) Draw seg RS.

(5) Construct the perpendicular bisector of seg RS.

(6) Name the point of intersection of ray QS and the perpendicular bisector of RS as P.

(7) Draw seg PR.Therefore, ΔABC is the required triangle