Question

021): The volume of a cuboid is
11664 cubic centimeter. If its length
is 36 cm and breadth is 27 cm, find
the height of the cuboid ?"
O A 21 cm
OB:25 cm
O C:121 cm
OD:12 cm​

Answer 1

Answer:

12cm

Step-by-step explanation:

Volume=l×b×h

11664=36×27×h

11664=972×h

11664÷972=h

12=h

Answer 2

Given : The volume of a cuboid is 11664 cm³ . it's length is 36 cm and breadth is 27 cm .

Need To Find : Height of the Cuboid.

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❍ Let's Consider Height of Cuboid be x cm .

$\dag\frak{\underline {As,\:We\:know\:that\::}}$

$\star\boxed {\pink{\sf{ Volume _{(Cuboid)} = l \times b \times h \:cu.units }}}$

Where,

• l is the Length of Cuboid, b is the Breadth of Cuboid & h is the Height of Cuboid.

⠀⠀⠀⠀⠀⠀$\underline {\bf{\star\:Now \: By \: Substituting \: the \: Given \: Values \::}}$

$:\implies \sf{ 11664 = 27 \times 36 \times x }\\\\:\implies \sf{ 972 \times x = 11664 }\\\\:\implies \sf{ x = \cancel {\dfrac {11664}{972}}}\\\\\underline {\boxed{\pink{ \mathrm {  x = 12\: cm}}}}\:\bf{\bigstar}$

Therefore,

⠀⠀⠀⠀⠀$\therefore {\underline{ \mathrm {  Hence,\:Height \:of\:Cuboid \:is\:\bf{12\: cm}}}}$

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$\large {\boxed{\sf{\mid{\overline {\underline {\star More\:To\:know\::}}}\mid}}}$

⠀⠀⠀⠀⠀⠀⠀⠀⠀⠀$\begin{gathered}\boxed{\begin {array}{cc}\\ \dag\quad \Large\underline{\bf Formulas\:of\:Areas:-}\\ \\ \star\sf Square=(side)^2\\ \\ \star\sf Rectangle=Length\times Breadth \\\\ \star\sf Triangle=\dfrac{1}{2}\times Breadth\times Height \\\\ \star \sf Scalene\triangle=\sqrt {s (s-a)(s-b)(s-c)}\\ \\ \star \sf Rhombus =\dfrac {1}{2}\times d_1\times d_2 \\\\ \star\sf Rhombus =\:\dfrac {1}{2}p\sqrt {4a^2-p^2}\\ \\ \star\sf Parallelogram =Breadth\times Height\\\\ \star\sf Trapezium =\dfrac {1}{2}(a+b)\times Height \\ \\ \star\sf Equilateral\:Triangle=\dfrac {\sqrt{3}}{4}(side)^2\end {array}}\end{gathered}$

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