Question

022 x 10^23 molecules of urea are present in 100ml solution.The concentration of urea solutiin is

Answer 1

Moles of urea = molecules/avogadro no

= 6.02X10^20 / 6.022 X 10^23

= 10^-3 moles

So it will have 10^-2 mole in 1 litre of solution

because

Molarity/concentration = mole / litre

= 10^-3/1L

= 10^-2M