Question

023/60 Number of unit cells in 1 g of X (atomic mass = 40)
which crystallizes in simple cubic pattern is
(NA = Avogadro number)​

Answer 1

Answer:

Potassium crystallizes in a body-centered cubic lattice with edge length, a=5. 2 Ao. How many nearest neighbours does each K atom have? In BCC lattice, the number of nearest atom or coordination number is equal to 8.

Explanation:

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Answer 2

Given:

The atomic mass of X, M = 40 gm

The given mass of X = 1 gm

It crystallizes in simple cubic pattern.

To Find:

The total no of unit cells in 1 g of X.

Calculation:

- For simple cubic pattern, z = 1

- The volume of 1 g of X = Mass / Density

⇒ The volume of 1 g of X = 1/d

- We know that:

V × NA × d = z × M

⇒ V × 6.022 × 10²³ × d = 1 × 40

⇒ Volume of 1 unit cell = 40 / (6.022 × 10²³ × d)

- No of unit cells = Volume of 1 gm of X / Volume of 1 unit cell

⇒ No of unit cells = (1/d) / {40 / (6.022 × 10²³ × d)}

⇒ No of unit cells = (6.022 × 10²³) / 40 = 0.15055 × 10²³

⇒ No of unit cells = 15.055 × 10²¹

- So, the total no of unit cells in 1 g of X is 15.055 × 10²¹.