Question

026) An ammeter of resistance 0.80 O can measure current upto 1.0 A

(1) What is the combined resistance of the ammeter and the shunt?​

Answer 1

(i) The net resistance of ammeter with shunt connected in parallel=R2​=RA​+xRA​x​

=0.8+x0.8×x​

The potential of the cell is

V=I1​RA​=I2​R2​

⟹1×0.8=5×0.8+x0.8x​

⟹x=0.2Ω

(ii) Combined resistance of the ammeter and thus shunt

R=0.8+x0.8x​=0.16Ω