Question

027. If the zeros of the polynomial r3 - 3x2 + x + 1are a - b,a, a + b, find 'a' and 'b'.
Or
If two zeros of the polynomial x4 - 6x3 - 26x2 + 138x - 35are 2 +-root 3 find the
other zeros.​

Answer 1

Answer:

x = 7 or x = -5

Step-by-step explanation:

(x - $2 - \sqrt{3$ ) (x - $2 + \sqrt{3}$)

(x-2)^2 - (root3)^2

$x^{2} - 4x +1$

divide x4 - 6x3 -26x2 +138x - 35 by x2 -4x +1 by long division

then,

factorise the quotient using splitting the middle term

therefore x = 7 or x = -5

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