Question

027. Without repetition of the numbers, four-digit
numbers are formed with the numbers 0,2,3,
5. The probability of such a number divisible
by 5 is
(A) 1/5
(B) 4/5
(C) 59
(D) 3/9​

Answer 1

Answer:

[0,2,3,5]

The number can't be formed starting zero

∵ Total numbers formed start with 2 ⇒3!=6

3⇒ 3!=6

5⇒ 3!=6

Then, total no, from ⇒ 18 ways

Now, the no should be divisible with 5 that means now to end with 0 and 5

⇒ Such No ⇒ 4+4+2=10

then probability =

18

10

=

9

5