Question

028. A car starts with velocity 10 m s' and accelerates at 5 ms. Find the final velocity
the car has travelled a distance 30 m.​

Answer 1

Answer:

Given :-

• Initial velocity = 10 m/s
• Acceleration= 5 m/s
• Distance = 30 m

To Find :-

Final velocity

Solution :-

We will use 3rd equation of motion

v² - u² = 2as

$\sf \: {v}^{2} - {10}^{2} = 2(5)(30)$

$\sf \: v {}^{2} - 100 = 300$

$\sf \: {v}^{2} = 300 + 100$

$\sf \: v {}^{2} = 400$

$\sf \: v = \sqrt{400}$

$\mathfrak \red{v = 20 \: {ms}^{ - 1}}$

Hence :-

Final velocity is 20 m/s.

Answer 2

To Find:-

• Find the final velocity of the car.

Given:-

• The car starts with a velocity of 10m/s and accelerates at 5m/s ².
• The car travelled at a distance of 30m.

$\huge\tt † \: \underline { We \: \: know \: \: that}:$

• u = initial velocity
• v = final velocity
• a = accelaration
• s = distance
• t = time

$\tt\implies \: {v}^{2} - {u}^{2} = 2as$

$\tt\implies \: {v}^{2} - {10}^{2} = 2(5)(30)$

$\tt\implies \: {v}^{2} - 100 = 300$

$\tt\implies \: {v}^{2} = 300 + 100$

$\tt\implies \: v = \sqrt{400}$

$\tt \implies \: v = 20m/s$