Question

028 Find the area of triangle, two of
which side of 8 cm and 11 cm and perimeter is 32​

Answer 1

A=s(s﹣a)(s﹣b)(s﹣c)

P=a+b+c

s=a+b+c

2

Solving forA

A=1

4﹣P4+4P3a+4P3b﹣4(Pa)2﹣12P2ab﹣4(Pb)2+8Pa2b+8Pab2=1

4·﹣324+4·323·8+4·323·11﹣4·(32·8)2﹣12·322·8·11﹣4·(32·11)2+8·32·82·11+8·32·8·112≈43.8178cm²

ANSWER:

43.8178cm Squared

Answer 2

A=s(s﹣a)(s﹣b)(s﹣c)

P=a+b+c

s=a+b+c

2

Solving forA

A=1

4﹣P4+4P3a+4P3b﹣4(Pa)2﹣12P2ab﹣4(Pb)2+8Pa2b+8Pab2=1

4·﹣324+4·323·8+4·323·11﹣4·(32·8)2﹣12·322·8·11﹣4·(32·11)2+8·32·82·11+8·32·8·112≈43.8178cm²

ANSWER:

43.8178cm Squared