Question

03. A boy walks 300 m towards East and then 250 m towards North. The distance of the boy from the starting point is ​

Answer 1

Answer:

250m

Step-by-step explanation:

By Pythagoras theorem

The required distance

= √(2002 + 1502)

= √(40000+ 22500)

= √(62500)

= 250m

So the distance of the girl from the starting point is 250m

Answer 2

Following are the steps for getting the answer:

Given:

a boy walks towards East =300m

and then towards North=250 m

To find:

The distance of the boy from the starting point

Solution:

we have to find the distance of the boy from the starting point

given that,

A boy walks 300 m towards East and then 250 m towards North

so, it will make a right angle

so we can use a Pythagoras theorem

let the distance be d

Let, a boy walks towards East is x

and  towards North will is  y

x=300m

y=250m

we know that,

Hypotenuse² =  Perpendicular² + Base²

d²=x²+y²

d²=300²+250²

d²=90000+62500

d²=152500

d=√152500

d=390.512

thus,  The distance of the boy from the starting point is ​390.512m