Question

03. Factors of x4 + 4x2 + 3 will be (Hint: here you can suppose x? as y)
(i) (x² + 4)(x2 + 1)
(ii) (x2 + 3)(x + 1)
(111) (x2 + 3)(x2 + 2)
(iv) (x2 + 3)(x2 + 3)​

Answer 1

Step-by-step explanation:

let x² = y, then x⁴ = y²

y²+4y+4 -1 (3 =4-1)

y²+2*y*2 +2² -1

it is in form a²+2ab+b² = (a+b)², where a=y, b=2

(y+2)²-1²

a²-b² = (a+b)(a-b), a=y+2, b=1

= (y+2-1)(y+2+1)

=(y+1)(y+3)

=(x²+1)(x²+3)