Question

03
find the compound introst an IP 20
2000 are invested for 3 yeas, un
the rade
g
10 pcopia .​

Answer 1

Correct question ::-

Find the compound interest on principal Rs. 2000 , time 3 years and the rate of 10%.

Given ::-

• Principal = Rs. 2000

• Time taken = 3 yrs.

• Rate% = 10%

To find ::-

• Find compound interest ?

Formula used ::-

$: ⟹ \: A \: \: = P\: \times (1 + \dfrac{r}{100} ) \times T$

Solution ::-

_____________

$: ⟹ \: a \: \: \: = \: \: 2000 \times (1 + \dfrac{10}{100} ) \times 3$

$: ⟹ \: a \: \: \: = \: \: 2000 \times(\dfrac{100 + 10}{100} ) \times 3$

$: ⟹ \: a \: \: \: = \: \: 20\cancel{00} \times(\dfrac{110}{\cancel{100}} ) \times 3$

$: ⟹ \: a \: \: \: = \: \: 20 \times110 \times 3$

$: ⟹ \: a \: \: \: = \: \:6600$

_________

Amount = Principal - compound interest

$: ⟹ 6600 = 2000 - C.I.$

$: ⟹C.I. = 6600 - 2000$

$: ⟹$ C.I. = Rs. 4600

____________

Hence , the compound interest = Rs. 4600

Let's explore more ::-

• P = principal

• R = rate

• T = time

• C.I. = compound interest

• A = Amount

Answer 2

Correct question:

• Find the compound interest on principal Rs. 2000 , time 3 years and the rate of 10%.

Given:

• Principal = Rs. 2000
• Time taken = 3 yrs.
• Rate% = 10%

To find:

• Compound interest

Solution:

Here Formula used = A = P × ( 1 + r/100) × T

Putting the values,

→ A = 2000 × ( 1 + 10/100) × 3

→ A = 2000 × ( 100 + 10 /100) × 3

→ A = 2000 × ( 110 / 100) × 3

→ A = 20 × 110 × 3

→ A = 6600

According to the question,

Amount = Principal - compound interest

→ 6600 = 2000 - C.I

→ C.I = 6600 - 2000

→ C.I = 4600

Hence,

• Compound interest :- ₹4600