Question

03 find the position vector of a point c which
divides the Join of points with position
vectors a+b and 2a+b internally
in the batio 1:2​

Answer 1

Answer:

$Given: OA=2a−3b$

$</p><p></p><p>OB=6b−a</p><p>$

$Since P divides AB in 1:2 internally, so, OP=1+21.OB+2.OA=1+21.(6b−a)+2.(2a−3b)</p><p>$

$Therefore, OP=33a=a</p><p></p><p>$

$\boxed{f} \red{o} \boxed{l} \pink{l}\boxed{o} \green{w} \: \: \boxed{m} \purple{e}$

Answer 2

Answer:

above answers will help u okk dude