Question

03: find the value of <Y.
140°
40-
45-​

Answer 1

Answer:

Explanation:

We know that, median =  

Where, l = lower limit of medial class

n/2 = Half of sum of frequencies

cf = cumulative frequency of class preceding medial class

f = frequency of medial class

and h = class size

Here,

l = 55 (since 58 lies between 55 - 65, medial class would be 55 - 65)

n = 140

→ n/2 = 70

cf = 8 + 10 + x + 25 = 43 + x

f = 40

h = 10

and median = 58

So, applying the formula we get,

27 - x = 12

→ x = 15

Now, sum of frequencies = 140

→ 8 + 10 + x + 25 + 40 + y + 15 + 7 = 140

→ 105 + x + y = 140

→ 105 + 15 + y = 140

→ y = 20