Question

03
i. AABD is a triangle in which ZA=90° and seg AC I seg BD Show that
i) AB2=BC.BD ii) AD2BD.CD
iii) AC2=BC.CD
i) In AABD, ZBAD=90°
(Given)
seg AC I hypotenuse BD
.. In ABCA-AACD-ABAD
(Similarity in Right-angled triangle)
ii) ABCA- ABAD
... (From (i))
A
BC
BA
... (c.s.s.t)
=BD.CD
... (From (1)
.(c.s.s.t)
B
iii) AACD- ABAD
CD
AD
=BD.CD
D
C
iv) ABCA ~AACD
AC
DC
(From (1)
... (c.s.s.t)
.: AC2​

Answer 1

Answer:

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