Question

03.Mixing 4 moles of A with 4 moles of B
forms 2 moles of C at equilibrium ,
according to the reaction:
A(g) + B(g) –> C(g) + D(g).
The value of equilibrium constant is:​

Answer 1

STEP BY STEP EXPLANATION

We have

A + B -> C + D

Initially. 4 4 0 0

At equilibrium, 2 moles of the compound 'C' is formed hence, 2 moles are dissociated from LHS

i.e. A + B -> C + D (At equilibrium)

4-2 4-2 2 2

=2 =2

As we know

$k_{c} = \frac{a \times b}{c \times d} = \frac{2 \times 2}{2 \times 2} = 1$

Hence, equilibrium constant=1