Question

03. Two years ago, a father was five times as old as his son. Two years later,
his age will be 8 more than three times the age of the son. Find the
present ages of father and son.​

Answer 1

Step-by-step explanation:

ANSWER

Let father age be x, his son age be y.

Before 2 years,

⇒(x−2)=5(y−2)−−−−−−−(1)

After 2 years

⇒(x+2)=8+3(y+2)−−−−−−−−(2)

From (1) x−5y+8=0

From (2)

⇒x+2−3y−6−8=0

⇒x−3y−12=0

Solving them

⇒−2y+20=0

⇒y=10

When y=10,x=42

So the present age of the father is 42 and the son age is 10

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Answer 2

Answer:

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