Question

030. if \alpha,\beta are the zeros of polynomial x^2+6x+2,then(1/\alpha+1/\beta)=?​

Answer 1

Answer:

the have given that α and β are the zeroes of the equation x² + 6x + 2

α + β = -b/a = -6 /1 = -6

αβ = c/a = 2 /1 = 2

1/α + 1/β = α+β /αβ

so substituting the values we get

= -6/2

= -3

so 1/α +1/β = -3

Step-by-step explanation:

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